Quiz Tomorrow! 9/26

Part A.
How would you simplify the following problem remembering that the minus must be changed to a plus -1 then the -1 distributed?
(2x - 3) - (4x - 6)

Now that you've combined the like terms could you solve for x?
(2x - 3) - (4x - 6) = 13

Part B.
Try a few problems using the steps you used in Part A. Show your work.
1. (3 - 9x) - (-1x + 4) = 9 2. -2(2x - 3 + x) = 9

Part C.
How would you utilize the laws of exponents and your knowledge of like terms to simply the following:
4(x^2y^2)^2 / 2x^3y^6


Part D.
If you are having difficulty, break it down…
1. On top use power to a power to include the square into the x2 and y2 within the parentheses

2. Now separate the parts then divide the numbers and use quotient laws for the variables
numbers x's y's

3. Is your solution 2x/y^4? If not, try again you'll get it! If so, you got it!

Part E.
Try a few problems using the steps you used in Part D.
1. 2.

Part F.
Choose 3 examples completed in class or for homework that were difficult for you and recopy them below. Do not copy the answers! Try and solve them then check your answers with what was done in class.
1. 2. 3.

Part G.
Simplify and solve the problems done on the last quiz. Can you get them now?
1a. Simplify the expression. 5g^5h^6 * 2g^4h^-2
2b. Evaluate the simplified expression for g = 2 and h = -1

3. Simplify the following problems:
(25y^2 + 5y +4) + -1 (-9y^2 – 12y – 7) (25y^2 + 5y +4) - (-9y^2 – 12y – 7)
*hint change the minus in the middle to a plus -1. then distribute the one. Now doesn’t it look like the first problem?